The grams of oxygen present in a sample of this compound that contains 56.00 grams of S = 41.9g of oxygen.
The compound contains the following:
Sulphur = 57.20%
Oxygen = 100 - 57.20 = 42.80%
If 57.20% of the sample contains 56g of Sulphur, then 42.80% of the sample will contain X.
Make X the subject of formula,
X = 42.8 × 56/57.20
X= 1712/57.20
X= 41.9g of oxygen
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