Answered

a monolayer containing 3.18×10-6 g of oleic acid has an area of 20.0 cm2. the density of oleic acid is 0.895 g / ml. what is the thickness of the monolayer (the length of an oleic acid molecule)? 5.69×10-5 cm 1.42×10-7 cm 7.11×10-5 cm 5.63×10-6 cm 1.78×10-7 cm



Answer :

The thickness of the monolayer is 1.777 × 10⁻⁷ cm

Calculation

Using,

Density = Mass / Volume

It is given that:

Area = 20.0 cm²

Density = 0.895 g/mL

Mass = 3.18 × 10⁻⁶ g

Then, applying the density formula as:

0.895 g/mL = 3.18 × 10⁻⁶ g / Volume (ml)

Volume = 3.55 × 10⁻⁶ mL

Since, 1 mL = cm³

So, Volume = 3.55 × 10⁻⁶ cm³

Thickness of monolayer =?

Also, Volume = area x thickness

So, then we have

Thickness = Volume/Area = 3.55 × 10⁻⁶ cm³ / 20.0 cm²

= 1.777 × 10⁻⁷ cm

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