Answer:
C and B
Step-by-step explanation:
Evaluate g(5) then substitute the value obtained into f(x)
g(5) = [tex]\sqrt{5-1}[/tex] = [tex]\sqrt{4}[/tex] = 2 , then
f(2) = 3(2) + 1 = 6 + 1 = 7
-----------------------------------------------------------------------------
f(x) = [tex]\frac{x^2+3}{(x-4)(x+8)}[/tex]
the denominator of f(x) cannot be zero as this would make f(x) undefined.
equating the denominator to zero and solving gives the values that x cannot be and if the numerator is non zero for these values then they are vertical asymptotes.
(x - 4)(x + 8) = 0
equate each factor to zero and solve for x
x - 4 = 0 ⇒ x = 4
x + 8 = 0 ⇒ x = - 8
the vertical asymptotes are x = 4 and x = - 8
