The function value at the minimum is -9
The function is given as:
f(x) = x^2 - 6x
Differentiate the function
So, we have
f'(x) = 2x - 6
Set the function to 0
So, we have
2x - 6 = 0
This gives
2x = 6
Divide by 2
x = 3
Substitute x = 3 in f(x) = x^2 - 6x
f(3) = 3^2 - 6(3)
Evaluate
f(3) = -9
Hence, the function value at the minimum is -9
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