The equation of the line is: y = 4x + 37
m = 4
b = 37
How to Write the Equation of a Line in Slope-intercept Form?
The equation of the line that is perpendicular to x + 4y = 12, will have a slope that is the negative reciprocal of the its slope.
Rewrite the equation, x + 4y = 12 in slope-intercept form:
4y = -x + 12
y = -x/4 + 3
The slope is -1/4. Therefore, the slope of the perpendicular line would be 4.
Substitute m = 4 and (a, b) = (-8, 5) into y - b = m(x - a)
y - 5 = 4(x - (-8))
y - 5 = 4x + 32
y = 4x + 32 + 5
y = 4x + 37
The equation of the line is: y = 4x + 37
m = 4
b = 37
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