Simon wanted to find the equation of a line that passes through (–6, 5) and is perpendicular to the graph of 3x + 2y = –11. His work is shown below.

1. 3x + 2y = –11 written in slope-intercept form is y = x , so the slope is .

2. The slope of the perpendicular line is .

3. Substitute the point and the new slope into point-slope form to get y – 5 = (x – (–6)).

4. Simplifying, the line is y – 5 = (x + 6).

Is Simon’s work correct?

No, the slope of the line 3x + 2y = –11 is not .
No, the slope of the line perpendicular to the line 3x + 2y = –11 should be .
No, he did not substitute the point and the slope into point-slope form correctly.
Yes, the work is correct.