Answer :
The distance the slower and faster car travelled are 360 km and 432 km respectively.
How to find the distance travelled by each car?
Two cars start at the same time from two towns 792 kilometres apart and meet in 9 hours.
One car can travel 8 km faster than the other car.
let
x = speed of the slower car
x + 8 = speed of the faster car
The cars meet in 9 hours and both cover a distance of 792 km.
Therefore,
speed = distance / time
distance = time × speed
Hence,
9x + 9(x + 8) = 792
9x + 9x + 72 = 792
18x = 792 - 72
18x = 720
divide both sides by 18
x = 720 / 18
x = 40
Therefore,
speed of the slower car = 40 km per hour
speed of the faster car = 48 km per hour
Hence,
how far the slower car go(distance) = 40 × 9 = 360 km
how far the faster car go(distance) = 48 × 9 = 432 km
learn more on distance and speed here: https://brainly.com/question/26662514
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