Answer :
From the interquartile range of the distribution, the fences for non-outliers are given as follows:
- Lower: 0.
- Upper: 657.65.
What is the missing information?
The quartiles of the distribution are given as follows:
- Q1: 273.8. (violent crimes per 100,000 population)
- Q3: 529.7. (violent crimes per 100,000 population)
What is the interquartile range and how it is related to outliers?
The interquartile range of a distribution is given by the difference of the third quartile by the first quartile, that is:
IQR = Q3 - Q1.
Outliers are given by:
- 1.5 IQR below Q1.
- 1.5 IQR above Q3.
For this problem, the IQR is:
IQR = 529.7 - 273.8 = 255.9.
Hence the fences are:
- Lower: 273.8 - 1.5 x 255.9 = -110.05, negative numbers are not possible in the range of the question, hence the lower fence is of 0.
- Upper: 273.8 + 1.5 x 255.9 = 657.65.
More can be learned about the interquartile range of a distribution at https://brainly.com/question/17083142
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