Answer -
[tex] \frac{61}{4} [/tex]
Step-by-step explanation:
Greetings !
Given expression( function )
[tex]h(x) = \frac{12}{2x} + 16[/tex]
Thus, plug in -8 in the variable x and solve as follows:-
[tex]h( - 8) = \frac{12}{2( - 8)} + 16[/tex]
Multiply the numbers 2.(-8) = -16
[tex] = \frac{12}{ - 16} [/tex]
Apply the fraction rule
[tex] \frac{a}{ - b} = - \frac{a}{b} [/tex]
[tex] = - \frac{12}{16} [/tex]
[tex] = - \frac{ 12}{16} + 16[/tex]
cancle
[tex] \frac{12}{16} = \frac{3}{4} [/tex]
Factor the number: 12 = 4.3
[tex] = \frac{4.3}{16} [/tex]
Factor the number 16 = 4.4
[tex] = \frac{4.3}{4.4} [/tex]
cancel the common factor =4
[tex] = \frac{3}{4} [/tex]
Thus,
[tex] = \frac{ - 3}{4} + 16[/tex]
Convert 16 to fraction :
Apply the fraction rule
[tex]a = \frac{ab}{b} [/tex]
[tex] = \frac{16.4}{4} [/tex]
Multiply the numbers 16.4=64
[tex] = \frac{64}{4} [/tex]
[tex] = - \frac{3}{4} + \frac{64}{4} [/tex]
Apply the fraction rule
[tex] \frac{a}{c} + \frac{b}{c} = \frac{a + b}{c} [/tex]
[tex] = \frac{ - 3 + 64}{4} [/tex]
Add the numbers -3+64 ==61
[tex] = \frac{61}{4} [/tex]
Hope it helps !!
