The equation of the line is [tex]5y+4x-35=0[/tex]
Given,
Point is (5,3)
Slope m=-4/5
so formula of equation of line is
[tex](y-y_{1})=m(x-x_{1})[/tex]
[tex](y-3)=-4/5(x-5)[/tex]
[tex]5y-15=-4x+20\\5y+4x-15-20=0\\5y+4x-35=0[/tex]
A line's equation can be formed using the slope of the line and a point on the line. To better understand the formation of a line equation, let us learn more about the slope of the line and the required point on the line. The slope of a line is its inclination with respect to the positive x-axis, and it is expressed as a numeric integer, fraction, or the tangent of the angle it makes with respect to the positive x-axis. The term "point" refers to a coordinate system point with the x and y coordinates.
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