Answer :
The percent by mass in the solution is 40.1%
Take a sample of this solution equal to 1 L. Utilize the supplied density to calculate its mass.
1.00L * 1000mL /1L * 1.47 g/mL = 1470 g
This 1.00-L solution will now include
n=c*V
c=n V
n=3.47 moles/L*1.00Lfrom n=3.47moles/L*1.00L.
Calculate how many grams of silver nitrate would contain this many moles 3.47 by using the molar mass of the compound.
mols of AgNO3
169.87 g*1 mole AgNO3 = 589.4 g AgNO3
The mass of the solute, in your case silver nitrate, is divided by the mass of the solution and multiplied by 100 to determine the solution's percent concentration by mass.
%w/w = Mass of solute/mass of solution x100
%w/w=589.4g
1470g×100=40.1%
The percent by mass in the solution is 40.1%
