The moles of na₂so₄ are in a 0.140 m aqueous solution that was prepared with 2.30 kg of water is 0.00032moles
The formula for calculating the molarity of a substance is expressed as;
molarity = moles/Volume
Given the following parameter
Molarity = 0.140M
volume = mass/density
Volume = 2.30/997 kg/m³
Volume = 0.0023m³
Determine the required moles
Moles of na₂so₄ = molarity * volume
moles of na₂so₄ = 0.140 * 0.0023
moles of na₂so₄ = 0.00032moles
Hence the moles of na₂so₄ are in a 0.140 m aqueous solution that was prepared with 2.30 kg of water is 0.00032moles
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