Over the interval 4 ≤ x ≤ 8, does f(x) or g(x)=2x^2+x-1 have a greater average rate of change? Show your work below.
The X coordinates for this interval should be 4, 8 with the y coordinates being 0, 14
I just don't understand what the difference between f(x) and g(x) is supposed to be



Answer :

Answer:

Function g(x) has the greater average rate of change over the given interval.

Step-by-step explanation:

The average rate of change of function f(x) over the interval a ≤ x ≤ b is given by:

[tex]\sf \dfrac{f(b)-f(a)}{b-a}[/tex]

Given:

  • f(4) = 0
  • f(8) = 14

Therefore, the average rate of change for the function f(x) over the given interval 4 ≤ x ≤ 8 is:

[tex]\sf \implies\dfrac{f(8)-f(4)}{8-4}=\dfrac{14-0}{8-4}=3.5[/tex]

Work out values of function g(x) for x = 4 and x = 8:

[tex]\implies \sf g(4)=2(4)^2+(4)-1=35[/tex]

[tex]\implies \sf g(8)=2(8)^2+(8)-1=135[/tex]

Therefore, the average rate of change for the function g(x) over the given interval 4 ≤ x ≤ 8 is:

[tex]\implies \sf \dfrac{g(8)-g(4)}{8-4}=\dfrac{135-35}{8-4}=\dfrac{100}{4}=25[/tex]

Therefore, function g(x) has the greater average rate of change over the interval 4 ≤ x ≤ 8, as 25 > 3.5.