Find the area and perimeter.

The figure shows a rectangle. The length of the rectangle is given by 9 x units. The width of the rectangle is given by 2 x plus 7 units.

18x2 + 63x; 22x + 14
63x2 + 16; 22x + 14
18x2 + 63x; 16x + 2
63x2 + 18; 11x + 7



Answer :

The area and the perimeter are 18x^2 + 63x and 22x + 14

How to determine the area and the perimeter?

The given parameters are

Length = 9x

Width = 2x + 7

The area is calculated as

Area = Length * Width

So, we have

Area = 9x * (2x + 7)

This gives

Area = 18x^2 + 63x

The perimeter is calculated as

P = 2 * (Length + Width)

So, we have

P = 2 * (9x + 2x + 7)

Evaluate

P = 22x + 14

Hence, the area and the perimeter are 18x^2 + 63x and 22x + 14

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