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1. 34g of CaCO3 was heated and decomposed completely. The reaction equation is shown below.
CaCO3(s) --> CaO(s) + CO2(g)

1.1 calculate the number of moles of CaCO3 that decomposed
1.2. Calculate the number of particles of CaO that can be produced



Answer :

pstnonsonjoku

The number of particles produced is 8.1 * 10^21 particles.

What is number of particles?

The equation of the reaction is; [tex]CaCO3(s)-- > CaO(s) + CO2(g)[/tex]. We can be able to obtain the number of moles of the calcium carbonate can be obtained from;

Mass = 1.34 g

Molar mass = 100g

Number of moles =  1.34 g/ 100g = 0.0134 moles

Thus, the number of moles of carbonate that decomposed is  0.0134 moles

Given that the reaction is 1:1 and there are 6.02 * 10^23 particles in 1 mole of CaO, the number of particles of  CaO produced is;

0.0134 moles *  6.02 * 10^23 particles = 8.1 * 10^21 particles

Learn more about reaction equation:https://brainly.com/question/3588292

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