Answered

A graphing calculator is recommended.
If a ball is thrown into the air with an initial velocity of 42 ft/s, its height in feet after t seconds is given by
y = 42t − 16t2.
(a)
Find the average velocity of the ball (in ft/s) for the time interval beginning at t = 2 and lasting for each of the following.
(i)
0.5 seconds
ft/s
(ii)
0.1 seconds
ft/s
(iii)
0.05 seconds
ft/s
(iv)
0.01 seconds
ft/s
(b)
Use your answers from part (a) to estimate the instantaneous velocity (in ft/s) when
t = 2.
ft/s



Answer :

ogorwyne

The answers to the questions are

  • -30 ft/s
  • -23.fts
  • -22.8fts
  • -22.16 ft/s
  • -22ft/s

How to solve for the average velocity

We have the formula for y = 42t - 16t^2.

We have been given t to be = 2

The solution to the questions would be

0.5 seconds

(i) Average velocity =

s*(2.5) - s*(2)/0.5 =

-30 ft/s

(ii) average velocity =

0.1 seconds

[s*(2.1) - s*(2)]/0.1

= -23.6 ft/s

(iii) average velocity

0.05 seconds

s* (2.05) - s* (2)/0.05

= -22.8 ft/s

(iv average velocity at 0.01 seconds

[s* (2.01) - s* (2)]/0.01

= -22.16 ft/s

(b) the instantaneous velocity that would be felt is given as is -22 ft/s

Read more on average velocity here:

https://brainly.com/question/6504879

#SPJ1

Other Questions