The distance between point P and point T is 6.1 units.
Given that point P is located at (-3.7,1.8) and the point T is located at (2.4,1.8).
We are required to find the distance between point P and point T.
Distance is basically a variable which shows how far two points are located. It can be distance between two things also.
Distance between two points is calculated by the following points:
=[tex]\sqrt{(x_{2} -x_{1} )^{2} +(y_{2} -y_{1} )^{2} }[/tex] in which [tex](x_{1} ,y_{1} ),(x_{2} ,y_{2} )[/tex] are the points.
The points which are given as P(-3.7,1.9) and T(2.4,1.8).
Distance=[tex]\sqrt{(2.4+3.7)^{2}+(1.8-1.8)^{2} }[/tex]
=[tex]\sqrt{6.1^{2} }[/tex]
=6.1units
Hence the distance between point P and point T is 6.1 units.
Learn more about distance at https://brainly.com/question/17273444
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