Answer :
The equation of the line that passes through the point (-6,8) and has a slope of -5/3 is y=-5/3x-2.
Given that the line passes through the point (-6,8) and has a slope of -5/3.
We are required to find the equation of the line whose description is given.
Equation is basically the relationship between two or more variables that are expressed in equal to form. It may be linear equation, quadratic equation or cubic equation. Slope intercept form in the equation be y=mx+c.
We have been given slope be -5/3.
y=mx+c--------------1
Put m=-5/3 in equation 1.
y=-5/3x+c------------2
Put (-6,8) in equation 2.
8=-5/3 *(-6)+c
8=-5*(-2)+c
8=10+c
c=-2
Use the value of c in equation 2.
y=-5/3x-2
Hence the equation of the line that passes through the point (-6,8) and has a slope of -5/3 is y=-5/3x-2.
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