If 25 ml of 2.3 m naoh solution are poured into a beaker and diluted with pure water to a new volume of 80, what is the concentration of the new solution?



Answer :

The concentration of the new solution 0.71 M

It is given that:

initial volume of solution = 25 ml

concentration of solution = 2.3 m

volume of solution after dilution = 80 ml

We have to find:

concentration of solution after dilution

Molarity is define as moles of solute present in 1000 ml of solution. It's unit is given by mol/L or M. Here molarity is given by the formula

Here, M1V1 refers to mass and volume of 1 component and M2V2 refers to mass and volume of other component

M1V1 = M2V2

M2 = (V1/V2)*M1

M2 = 25/80*2.3 = 0.71 M

So, molarity of solution after dilution is 0.71 M

Learn more about Molarity here:

https://brainly.com/question/26873446

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