Answer :
The amount of [tex]4.10[/tex] mg carbon dioxide is 12/44 × 4.1 = 1.118 mg, or 0.093 millimole.
H =0.106 millimole is contained in 0.959 mg of water
(2/18 × 0.959=0.106 mg).
C:H is 1:1.14 in molar proportion.
Therefore, the empiric formula is approximate C7H8.
How can you determine the combustion analysis's molecular formula?
Determine the compound's empirical formula using the grams of carbon, hydrogen, and oxygen. Divide the supplied molecular mass by the empirical formula mass to obtain n, then compute the formula mass for the empirical formula. To obtain the molecular formula, multiply each subscript in the empirical formula by n.
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