The values of x are 0 < x < π/12 and 11π/12 < x < π
How to determine the values of x that satisfy the inequality?
The inequality expression is given as:
0<2 cos(2x)−√3
The interval is given as:
[0, π]
Rewrite 0<2 cos(2x)−√3 as:
√3 <2 cos(2x)
Further, rewrite as:
2cos(2x) > √3
Divide by 2
cos(2x) > √3/2
Next, we plot the above inequality on the interval [0, π]
From the graph of the inequality, the values of x are
0 < x < π/12 and 11π/12 < x < π
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