You are given a cube of lead that is 1.000 cm on each side. the density of lead is 11.35 . how many atoms of lead are in the sample?

Question

25-08-2022
Chemistry

Answered

You are given a cube of lead that is 1.000 cm on each side. the density of lead is 11.35 . how many atoms of lead are in the sample?

Answer :

Other Questions

A graduate student in a desk nearby also obtained an unknown sample and after performing some experiments to determine how much of each element is in the compou

A sample of aluminum with mass of 53.9 g is initially at 143 ∘C . What is the temperature of the aluminum after it loses 2.85 x 103 J ?

solids analysis is one of the most widely used parameters for assessing water quality. the following tests were performed on a water sample. the sample volume w

two samples of sodium chloride were decomposed into their constituent elements. one sample produced 8.00 g of sodium and 12.3 g of chlorine, and the other sampl

How many molecules are in 60 mg of vitamin C: C6H8O6 ?

6) There are 2 isotopes of copper that occur naturally; Cu-63 and Cu-65. The Cu-63 atoms have a mass of 62.930 amu and the Cu-65 atoms have a mass of 64.928 amu

consider two gases, a and b, that are in a container at room temperature. what effect will the following change have on the rate of the reaction between these g

A metal block has a density of 12.6 g/mL. If the block is cut into two identical pieces, what is the density of each piece? a. 6.3 g/mL b. Less than 12.6 g/mL c

1. Identify three surface processes that are part of the rock cycle. Explain the role of each process in the cycle. sc.7.E.6.2 0

smecloudbird18 smecloudbird18 · Answer 1 · 2022-09-01T04:40:46-04:00

You are given a cube of lead that is 1.000 cm on each side and the density of lead is 11.35 g/[tex]cm^{3}[/tex] then atoms of lead are 0.329 in the sample .

Calculation ,

density = 11.35 g/[tex]cm^{3}[/tex] ( given )

volume of cube = [tex]a^{3}[/tex] ( where a is the side of the cube )

side of cube = 1 cm

So volume of cube = 1 [tex]cm^{3}[/tex]

formula used : density = mass / volume

mass = density × volume = 11.35 g/[tex]cm^{3}[/tex] × 1 [tex]cm^{3}[/tex] = 11.35 g/[tex]cm^{3}[/tex]

number of mole of lead = mass/molar mass = 11.35 g/[tex]cm^{3}[/tex]/207.2 = 0.054 mol

The one mole of lead contain 6.022 ×[tex]10^{23}[/tex] atom

0.054 mole of lead contain 6.022 × [tex]10^{23}[/tex] × 0.054 atom

0.054 mole of lead contain 0.329 atoms .

To learn about Lead

https://brainly.com/question/13264277

#SPJ4