The points are; (7/2, -1/2).
What is the given point?
Now the tangent line is given as;20x 4y = 1. When we rewrite it in the slope intercept form, we have the equation as; y = 1 - 20x/4 or y = 1/4 - 5x.
Then to obtain the slope of the curve we have; y = 19 - 2x
dy/dx = 2
Using the relation;
m1m2 = -1
m2 = -1/2
Hence;
y = 1/4 - 5(-1/2)
y = 1/4 + 5/2
y = 7/2
Thus the points are; (7/2, -1/2)
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