Show that the triangle with vertices A(3, -1), B(5, -8), and C(-4, -3) is a right triangle by using the converse of the Pythagorean Theorem.
We must first find the length of all three sides of the triangle by finding the distance between the vertices.
d(A, B) =
d(B, C) =
d(A, C) =
Therefore, the following conclusion can be reached.
Since [d(A, B)]²+ [d(A, C)]²= [d(B, C)]2, it is a right triangle.
Since [d(A, B)]²+ [d(B, C)]²= [d(A, C)]2, it is a right triangle.
Since [d(A, C)]2+ [d(B, C)]² = [d(A, B)]2, it is a right triangle.
O Since all sides have the same length, it is a right triangle.
O Since all sides have different lengths, it is a right triangle.



Answer :

Based on the Pythagorean theorem, a. Since [d(A, B)]²+ [d(A, C)]²= [d(B, C)]², it is a right triangle.

What is the Pythagorean Theorem?

The Pythagorean theorem states that the square of the length of the longest side of a right triangle is equal to the sum of the squares of the lengths of the other two smaller sides of the right triangle.

Given the following:

A(3, -1),

B(5, -8),

C(-4, -3)

Using the distance formula, [tex]\sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}[/tex], find AB, BC, and AC.

AB = √[(5−3)² + (−8−(−1))²]

AB = √(4 + 49)

AB = √53 units

BC = √[(5−(−4))² + (−8−(−3))²]

BC = √(81 + 25)

BC = √106 units

AC = √[(3−(−4))² + (−1−(−3))²]

AC = √(49 + 4)

AC = √53 units

Applying the Pythagorean theorem, we have:

AB² + AC² = BC²

(√53)² + (√53)² = (√106)²

53 + 53 = 106

106 = 106

Thus, the triangle is a right triangle.

Therefore, we can conclude that, based on the Pythagorean theorem, a. Since [d(A, B)]²+ [d(A, C)]²= [d(B, C)]², it is a right triangle.

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