Point Q'Q ′ Q, prime is the image of Q(-7,2)Q(−7,2)Q, left parenthesis, minus, 7, comma, 2, right parenthesis under a translation by 888 units to the right and 222 units up. What are the coordinates of Q'Q ′ Q, prime?



Answer :

The transformation of Q(-7, 2) under a translation by 8 units to the right and 2 units up gives; Q"(1, 4)

How to carry out Translation Transformation?

We are told that coordinate of Point Q is;

Q(-7, 2)

Now, it undergoes transformation under a translation by 8 units to the right and 2 units up.

Now, when we translate a coordinate to the right, we will simply add the number of units of translation to the x-coordinate.

Thus, translation of Q(-7, 2) by 8 units to the right gives;

Q'(-7 + 8, 2) = Q'(1, 2)

Now, translation further by 2 units upwards means we add the number of units of translation to the y-coordinate.

Thus, translation of Q'(1, 2) by 2 units upwards gives;

Q''(1, 2 + 2) = Q"(1, 4)

Read more about Translation Transformation at; https://brainly.com/question/4289712

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