A line has a slope of -3/4 and passes through the point (-5, 4). Which is the equation of the line?

O y=-3x+1/2
O y=-3x+4
O y=-x-2
oy--x-1/4



Answer :

The equation of line which has slope -3/4 and passes through a point (-5,4) is given by          

y = -3/4x  +1/4

We have been given,

                       Slope = m = -3/4

                       Point = (x1,y1) = (-5,4)

The general slope-intercept form is given as,

              y = mx + c

                 where m = slope

                               c = intercept

Further, the formula to find the equation of line when we have been given one point and the slope is as follows,

            (y-y1) = m(x-x1)            (1)

Now putting the required value in equation (1) we will get,

       (y-4) = -3/4(x+5)

        y-4 = -3/4x – 15/4

         y = -3/4x – 15/4 + 4

         y = -3/4x  +1/4

Thus, the equation of line which has slope -3/4 and passes through a point (-5,4) is given by          

y = -3/4x  +1/4

Learn more about slope intercept form here : https://brainly.com/question/19440459

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