Determent the value of n that makes the polynomial a perfect square trinomial. Then factor as the square of a binomial. Express numbers as integers or simplified fractions.
y^2-3y+n
What is the value of n that makes the polynomial a perfect square?



Answer :

a. The value of n that makes the polynomial a perfect square trinomial is n = 9/4

b. The trinomial expresssed as the square of a binomial is (y - 3/2)²

What is a trinomial?

A trinomial is a mathematical expression that contains three terms.

What is a perfect square trinomial?

A perfect square trinomial is a polynomial of the form (a + b)²

a. How to find the value of n that makes the polynomial a perfect square trinomial?

Since we have the polynomial y² - 3y + n. We want to express it as a perfect square trinomial.

To be a perfect square trinomial, y² - 3y + n = (y - a)² =  y² - 2ay + a²

Comapring both expressions, -2a = -3 and n = a²

So, a = 3/2 and n = a²

= (3/2)²

= 9/4

So, y² - 3y + n = y² - 3y + 9/4

Thus, the value of n that makes the polynomial a perfect square trinomial is n = 9/4

b. How to express the trinomial as a the square of a binomial?

Since we have the trinomial  y² - 3y + 9/4

Expressing it a a binomial, we have

y² - 3y + 9/4 = y² - 3y + (3/2)²

= (y - 3/2)²

So, the trinomial expresssed as the square of a binomial is (y - 3/2)²

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