Balance the following skeleton reactions and identify the oxidizing and reducing agents:(b) CrO₄²⁻(aq) + Cu(s) → CrOH₃(s) + CuOH₂(s)



Answer :

The balanced skeleton reactions are given below

2CrO₄²⁻(aq) + 3Cu(s)  +8[tex]H_{2} O[/tex](l) → 2Cr(OH)₃(s) + 3Cu(OH)₂(s) + 6[tex]OH^{-}[/tex](aq)

The oxidising agent and  reducing agents are Cr and  Cu .

The following are involved in an basic medium's balancing redox reaction .

  1. The reaction should first be split into two half reactions
  2. Balance the atoms present in half reaction other than oxygen and hydrogen atoms .
  3. Add  [tex]H_{2}O[/tex] on that side where number of oxygen  atom is less to balance the oxygen atom .
  4. Add  [tex]H^{+}[/tex] on another side of in which water attached to make the hydrogen atom equal.
  5. Add [tex]OH^{-}[/tex] ions to both sides to neutralize  [tex]H^{+}[/tex] ion.
  6. Combine  [tex]H^{+}[/tex] and [tex]OH^{-}[/tex] ion to make [tex]H_{2} O[/tex] .
  7. Balance the charge by adding  [tex]e^{-}[/tex] .
  8. Now , add the two half reactions .

The species which reduces the other species in the redox reaction is called oxidizing agent . Similarly , the species which oxidize the other species in the redox reaction  is called reducing agent .

To learn more about reducing agents please click here ,

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