Consider the following reaction:2NOBr(g) ⇄ 2NO(g) + Br₂(g) K=0.42 at 373K Given that S° of NOBr(g) = 272.6J/mol·K and that ΔSrxn° and ΔHrxn° are constant with temperature, find(e) ΔGrxn° at 298K