The active compound in Pepto-Bismol contains C, H, O, and Bi.
(d) A dose of Pepto-Bismol contains 0.600 mg of active ingredient. If the yield of the reaction in part (c) is 88.0%, what mass (in mg) of bismuth(III) hydroxide is required to prepare one dose?



Answer :

A mass of 4.9 x 10^-4 g of bismuth hydroxide is needed to create one dosage.

Equation

[tex]3Bi(OH)_{3} +3HC_{7}H_{5} O_{3} \longrightarrow Bi_{3} C_{21}H_{15} O_{12}+3H_{2} O[/tex]

m(Bi3C21H15O12)=0.600mg=0.0006g

n(Bi3C21H15O12)=m/Mr=5,52*10^{-7} mol

n([tex]Bi(OH)_{3}[/tex] theor)= 3n (Bi3C21H15O12) = 1.67 x 10^{-6} mol

n([tex]Bi(OH)_{3}[/tex],exp)= 1.67 x 10^{-6} mol / yield = 1.88 x 10^{-6} mol

m([tex]Bi(OH)_{3}[/tex]} = n x Mr = 4.9 x 10^{-4} g

A mass of 4.9 x 10^-4 g of bismuth hydroxide is needed to create one dosage.

What constitutes the majority of Pepto-Bismol?

A fragile, crystalline, white metal with a faint pink undertone, bismuth is also brittle. It can be used in a wide range of products, such as cosmetics, alloys, fire extinguishers, and weapons. It is most famous for being the major component of stomach discomfort medications like Pepto-Bismol. A mass of 4.9 x 10-4g of bismuth hydroxide is needed to create one dosage.

What does Pepto-Bismol actually do?

This drug is used to treat nausea, heartburn, and sporadic stomach distress. Additionally, it is employed to cure and lessen the effects of travelers' diarrhea.

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