Answer :
To discover out the Ka of the solution, firstly, we will determine the pKa of the solution. At the equivalence point, the pH of the solution is equal to the pKa of the solution. Thus using Ka = – log pKa equation, we can quickly decide the price of Ka using a titration curve.
The acid dissociation regular (Ka) is used to distinguish strong acids from susceptible acids. Strong acids have rather excessive Ka values. The Ka cost is located by using looking at the equilibrium consistent for the dissociation of the acid. The greater the Ka, the more the acid dissociates.
How do you calculate Ka example?
As referred to above, [H3O+] = 10-pH. Since x = [H3O+] and you know the pH of the solution, you can write x = 10-2.4. It is now viable to find a numerical cost for Ka. Ka = (10-2.4)2 /(0.9 - 10-2.4) = 1.8 x 10-5.
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