Answer :
The empirical formula of C₃H₆O₂ (m =5, 240.20 g/mol) is C₃H₆O₂.
What is empirical formula?
The empirical formula for a chemical compound in chemistry is the simplest whole number ratio of atoms in a compound. Two simple illustrations of this concept are the empirical formulas of sulfur monoxide (SO) and disulfur dioxide (S2O2). As a result, sulfur monoxide and disulfur dioxide share the same empirical formula.
How to find the empirical formula?
The empirical formula (EF) mass is shown below.
Mw of C3H6O2 = 3 x (M of C) + 6x (M of H) + 2x (M of O)
= 3x (12,01 g/mol)+6x (1.01 g/mol) +2 x (16.00 g/mol)
= 74.09 g/mol
The whole number multiple for the compound is
Whole number multiple = [tex]\frac{74.08 g/mol}{74.09 g/mol}[/tex] ≈ 1
Since the whole number multiple, the molecular formula is also C3H6O2.
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