The value of n is 4 and yz is 1 if y is between x and z i.e. if y, x and z are collinear points.
According to the given question.
We have some linear equations.
xy = 4n + 3
yz = 2n - 7
and
xz = 20
Since, y is between x and z. Which means y, x and z are collinear points.
Therefore,
xy + yz = xz
⇒ 4n + 3 + 2n - 7 = 20
⇒ 6n -4 = 20
⇒ 6n = 20 + 4
⇒ 6n = 24
⇒ n = 24/6
⇒ n = 4
Therefore,
yz = 2n - 7 = 2(4) - 7 = 8- 7 = 1
Hence, the value of n is 4 and yz is 1 if y is between x and z i.e. if y, x and z are collinear points.
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