If a sample of the compound contains 7.4x10²¹ calcium ions, then number of iodide ion is 14.8x10²¹.
As calcium is an element in 4th row and group 2A. All atoms in this group prefers to form simple cation of +2charge.
Iodine is an element of group 17. All atoms in this group forms anion of -1 charge.
Now,
the oxidation state of calcium cation requires a reduction process. This reduction occurs in neutral iodine atom. It is initially present as diatomic molecule, with each iodine atom reduce to anion of -1 charge by getting 1 valence electron.
Base don these simple ion charges. Calcium iodide must combine in a ratio of 1:2 when forming a salt compound.
So, formula of Calcium iodide is CaI₂.
Hence,
number of iodine ion must be twice the number of calcium ion.
So,
Number of calcium ion = 7.4x10²¹
Number of iodide ion = 14.8x10²¹
Thus from the above conclusion we can say that, If a sample of the compound contains 7.4x10²¹ calcium ions, then number of iodide ion is 14.8x10²¹.
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