Answer :
The concentration of a solution (in m) prepared by diluting 37.00 ml of 0.250 m potassium chloride to 150.00 ml is 1.01 M .
Calculation ,
Formula used : [tex]M_{1} V_{1} = M_{2} V_{2}[/tex]
Where M is the morality or concentration of potassium chloride and V is the volume in ml .
Initial concentration ( [tex]M_{1}[/tex] ) = ?
Final concentration ( [tex]M_{2}[/tex] ) = 0.250
Initial volume ( [tex]V_{1}[/tex] ) = 37.00 ml
Final volume ( [tex]V_{2}[/tex] ) = 150.00 ml
Putting the value of Initial concentration , Initial volume and final volume in equation ( i ) we get .
[tex]M_{1}[/tex] × 37.00 ml = 0.250 × 150 ml
[tex]M_{1}[/tex] = 0.250 × 150 ml / 37.00 ml = 1.01 M
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