The perimeter of the rectangle is 24 units, and the area of the quadrilateral is 31.74 square units.
It is defined as the four-sided polygon in geometry having four edges and four corners. Two pairs of congruent sides and one pair of opposite congruent angles.
It is given that:
Quadrilateral ABCD with vertices A(3, 3), B(3, 7), C(9, 7), and D(12, 3).
(a) The perimeter:
By using the distance formula to get the distance between the points:
The distance formula can be given as:
[tex]\rm d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]
AB = 4
BC = 6
CD = 5
DA = 9
Perimeter of ABCD = 4 + 6 + 5 + 9
Perimeter of ABCD = 24 units
Area of the Quadrilateral ABCD:
A = √(12-4)(12-6)(12-5)(12-9)
A = √1008
A = 31.74 square units
Thus, the perimeter of the rectangle is 24 units, and the area of the quadrilateral is 31.74 square units.
Learn more about the quadrilateral here:
brainly.com/question/6321910
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