If the value of A is 24 units, B is 10 units in the right angled triangle then the value of C is 26 units.
Given that in a right angled triangle the value of A is 24 units and the value of B is 10 units.
We are required to find the value of C in that right angled triangle.
The triangle which is given is a right angled triangle and in this triangle we have to use pythagoras theorem.
Pythagoras theorem says that the square of hypothesis is equal to the sum of squares of perpendicular and base of that right angled triangle.
[tex]H^{2} =P^{2} +B^{2}[/tex]--------------1
In this triangle A is perpendicular, B is base and C is hypotenuse.
Using the values in 1.
[tex]C^{2} =A^{2} +B^{2}[/tex]
C=[tex]\sqrt{(24)^{2} +(100)^{2} }[/tex]
C=[tex]\sqrt{576+100}[/tex]
C=[tex]\sqrt{676}[/tex]
C=26 units
Hence if the value of A is 24 units, B is 10 units in the right angled triangle then the value of C is 26 units.
Learn more about pythagoras theorem at https://brainly.com/question/343682
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