The inequality that would be used for the least amount of amount of money she needs to deposit to avoid a fee is x ≥ $20.96.
According to the question
The given parameters:
Initial amount of money in Malcom's account = $638.54
A constant balance to be maintained to avoid a fee = $500
Amount to be withdrawn today = $159.50
Inequality that would be used to solve for the LEAST amount of money he needed to deposit to avoid a fee
Let the amount she deposits be x, then the least amount of money she needs to deposit to avoid a fee is given by the inequality:
$638.54 - $159.50 + x ≥ $500
$479.04 + x ≥ $500
x ≥ $500 - $479.04
x ≥ $20.96
Thus, the inequality that would be used to solve for the LEAST amount of money he needed to deposit to avoid a fee is x ≥ $20.96.
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