Answer :

The value of x in the pairs of similar triangles are:

5. x = 5

6. x = 5

7. x = 3

8. x = 7

How to Find the Side Lengths of Similar Triangles?

If two triangles are similar, their corresponding side lengths have the same ratio, that is, they are proportional to each other.

5. CD/UV = DE/VE [corresponding sides are proportional]

Substitute

15x - 3/30 = 156/65

(15x - 3)65 = (30)(156)

975x - 195 = 4680

975x = 4680 + 195

975x = 4875

x = 5

6. CD/CQ = CE/CR [corresponding sides are proportional]

Substitute

99/54 = 77/9x - 3

99(9x - 3) = (77)(54)

891x - 297 = 4158

891x = 4455

x = 5

7. UV/AB = VW/BC [corresponding sides are proportional]

Substitute

20/8 = 8x + 1/10

8(8x + 1) = (20)(10)

64x + 8 = 200

64x = 200 - 8

64x = 192

x = 3

8. QR/QK = QS/QL [corresponding sides are proportional]

Substitute

70/2x = 65/13

(70)(13) = (2x)(65)

910 = 130x

910/130 = x

x = 7

Therefore, the value of x in the pairs of similar triangles are:

5. x = 5

6. x = 5

7. x = 3

8. x = 7

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