Answer:
f₁(x) = -3x + 2
f₂(x) = x - 4
f₃(x) = x + 8
f₄(x) = -2x - 6
f₅(x) = -3x
Step-by-step explanation:
1). Since function f₁ (blue line) passes through a point (0, 2) and (-2, 8)
Let the equation of the blue line is,
y = mx + b
Since slope of the line 'm' = [tex]\frac{y_2-y_1}{x_2-x_1}[/tex]
m = [tex]\frac{8-2}{-2-0}[/tex]
m = -3
Y-intercept 'b' = 2
Therefore, equation of the line will be,
y = -3x + 2
Linear function representing the line will be,
f₁(x) = -3x + 2
2). Let the equation of the red line passing through (0, -4) and (2, -2) is,
y = mx + b
Slope of the line 'm' = [tex]\frac{y_2-y_1}{x_2-x_1}[/tex]
m = [tex]\frac{-4+2}{0-2}[/tex]
m = 1
y-intercept 'b' = -4
Therefore, the linear function will be,
f₂(x) = x - 4
3). Let the equation of the green line passing through (-6, 2) and (-2, 6) is,
y = mx + b
Slope of the line 'm' = [tex]\frac{6-2}{-2+6}[/tex]
m = 1
y-intercept 'b' = 8
Therefore, linear function will be,
f₃(x) = x + 8
4). Let the equation of the yellow line passing through (-6, 6) and (-4, 2) is,
y = mx + b
Slope of the line = [tex]\frac{6-2}{-6+4}[/tex]
m = -2
y-intercept of the line 'b' = -6
Therefore, function representing the line will be,
f₄(x) = -2x - 6
5). Let the equation of the pink line is passing through (0, 0) and (-2, 6) is,
y = mx + b
Since the line is passing through origin, y-intercept 'b' = 0
Slope of the line = [tex]\frac{6-0}{-2-0}[/tex]
m = -3
Therefore, equation of the linear function will be,
f₅(x) = -3x
