Answer:
Step-by-step explanation:
It depends on how it is written. By definition
[tex]\csc(x) = (\sin(x))^{-1} = \frac{1}{\sin(x)}[/tex]
[tex]\sec(x) = (\cos(x))^{-1} = \frac{1}{\cos(x)}[/tex]
[tex]\cot(x) = (\tan(x))^{-1} = \frac{1}{\tan(x)}[/tex]
however the functions
[tex]\sin^{-1}(x), \cos^{-1}(x), \tan^{-1}(x)[/tex] are the inverse functions of sine, cosine and tangent respectively. So, they are not equivalent functions
