Answer:
The answers to the question are
a. 166.64 ° F
b. 217990.08 J/hour or 60.55 J/s = 60.55 watts
c. 13.C
Explanation:
a. To solve the question we list out the given variables thus
mass of grain = 16.5 lbs
Temperature of grain = 67 °F
Volume of hot water = 5 gals = 0.02273 m³
Equilibrium temperature of the mixture = 154 °F
Specific heat capacity of the grain = 0.44 times specific heat capacity of water
Therefore we have
Heat supplied by hot water = heat gained by mixture
Density of the water = 997 kg/m³ which gives
Therefore the mass of the water = (Density of the water) × (Volume of the water) = (997 kg/m³) × (0.02273 m³) = 22.66181 kg
Therefore the heat supplied by the water =22.66 kg×1000 g/kg ×4.2 J/g°C×(Tₓ -67.78 °C) = 7.48 kg×1000 g/kg×0.44×4.2 J/g°C×(67.78 -19.44)
= 95172 × (Tₓ -67.78 °C) =668205.7536 J
(Tₓ -67.78 °C) = 7.02 from where Tₓ = 74.80 °C = 166.64 ° F
The initial temperature (strike temperature) of the hot water = 74.80 °C = 166.64 ° F
b. Where the mixture lost two degrees we have
22.66 kg×1000 g/kg ×4.2 J/g°C×2 °C + 7.48 kg×1000 g/kg×0.44×4.2 J/g°C×2 °C = 217990.08 J therefore the average energy lost per unit time = 217990.08 J/hour or 60.55 J/s
c. To find out how much it cost we have
Heat energy required to raise 5 gallons of water from 110 °F to 166.64 °F we have
22.66 kg×1000 g/kg ×4.2 J/g°C×(74.8 °C-43.33 °C) = 2994745.92 J
Energy lost during the heating = 10% = 299474.59 J
Total energy supplied 2994745.92 J + 299474.59 J = 3294220.5 J
Time for heating = 47 minutes, therefore rate of energy consumption = (3294220.5 J)/ (47×60) = 1168.163 Watt 1.168 kW
Cost of energy = 15.C per kilowatt-hour therefore 1.168 kW for 47 minutes will cost
1.168 kW ×47/60×15 = 13.C
therefore it cost 13.C to heat the 5 gallons of tap water initially at 110 ° F to the strike temperature 166.64 °F
Answers are 166.64 ° F, 60.55 J/s = 60.55 watts, and 13. C of temperatures.
The beer brewing starts with the steeping of the hot grains in water and the release of the sugars inside.
The sugar and fats inside the water are heated to a full boil and after which the hops are added. Thus the hot temperatures of the boil extracted oils from the hops and provides us sanitation from bacteria.
The beer is boiled with sugar in water and if 16.5 lbs of grains at 67 degrees of F are added to 5 gals on hot water then the temperature will strike 166.6 degrees F.
When the one-hour steeping stage the water is added and grains taken for mixing then at the 2 degrees the average energy is 217990.08 J/hours. For the enhancements, the boiling for the 110 degrees to stroke the temperature would be 166.5 F.
Find out more information about Beer brewing.
brainly.com/question/7177283.