Answered

Heng was trying to factor 10x^2+5x10x 2 +5x10, x, squared, plus, 5, x. She found that the greatest common factor of these terms was 5x5x5, x and made an area model: What is the width of Heng's area model?



Answer :

nandhini123

Answer:

Width of Heng's area model is  2x + 1

Step-by-step explanation:

Given:

[tex]10x^2+5x[/tex]

Greatest common factor is 5x

To Find:

The width = ?

Solution:

let the [tex]10x^2+5x[/tex] be the area

And  5x be the length

Then area  = length  x  width

Now rewriting the formula for width, we get

Width = [tex]\frac{area}{length}[/tex]

Substituting the values in the above formula

Width =[tex]\frac{10x^2+5x}{5x}[/tex]

Width = 2x + 1

View image nandhini123

The width is "2x+1".

Given:

[tex]\to area= 10x^2+5x\\\\\to length= 5x\\\\[/tex]

To Find:

width = ?

Solution:

Using formula:

[tex]\to \text{area = length} \times \text{width}\\\\[/tex]

As we know that area and length is given then width:

[tex]\to\text{width} = \frac{ \text{area}} {\text{length}} \\\\[/tex]

              [tex]=\frac{10x^2 +5x}{5x}\\\\=\frac{5x(2x +1)}{5x}\\\\= 2x + 1[/tex]

Therefore, the width is "2x+1".

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