Answer:
Characteristic time τ=20 s
When V = 15 m/s
t = 6.66 s
When V = 10 m/s
t = 20 s
When V = 5 m/s
t = 60 s
Explanation:
Given that
c=0.20 N/m(m/s)2
m = 80 kg
Vo=20m/s
Characteristic time τ=m/cvo.
[tex]\tau =\dfrac{m}{c.V_o}[/tex]
[tex]\tau =\dfrac{80}{0.2\times 20}[/tex]
Characteristic time τ=20 s
We know that velocity after t time given as follows
[tex]V =\dfrac{V_o}{1+\dfrac{\tau}{t}}[/tex]
When V = 15 m/s
[tex]15 =\dfrac{20}{1+\dfrac{20}{t}}[/tex]
t = 6.66 s
When V = 10 m/s
[tex]10 =\dfrac{20}{1+\dfrac{20}{t}}[/tex]
t = 20 s
When V = 5 m/s
[tex]5 =\dfrac{20}{1+\dfrac{20}{t}}[/tex]
t = 60 s